集合的isdisjoint函数

功能

  • 判断两个集合是否包含相同的元素 , 如果没有返回True , 否则返回False
  • 没有才返回True

用法

  • a_set.isdisjoint(b_set)

参数

  • b_set : 与当前集合用来判断的集合

返回值

  • 返回一个布尔值True或False

代码

# coding:utf-8
company_not_allow = {'女', '喝酒', '抽烟', '睡懒觉'}
one_player = {'男', '跑步', '朝气', '喝酒'}
two_player = {'女', '生活规律', '跆拳道'}
three_player = {'男', '太极拳'}
four_player = {'男', '空手道', '年轻'}
print(company_not_allow.isdisjoint(one_player))
print(company_not_allow.isdisjoint(two_player))
print(company_not_allow.isdisjoint(three_player))
print(company_not_allow.isdisjoint(four_player))
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